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If √𝑥+√𝑦=√𝑎, then 𝑑𝑦/𝑑𝑥 is(A) (−√𝑥)/√y(B) −1/2 √𝑦/√𝑥(C) −√𝑦/√𝑥(D) (−2√𝑦)/√𝑥 #maths
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If 𝑦=log_2𝑥 (√2𝑥), then 𝑑𝑦/𝑑𝑥 is equal to (A) 0(B) 1(C) 1/x(D) 1/√2𝑥
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If 𝑦=log_2𝑥 (√2𝑥), then 𝑑𝑦/𝑑𝑥 is equal to (A) 0(B) 1(C) 1/x(D) 1/√2𝑥
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