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Factoring a quadratic by diamond method
Learn how to factor quadratics using the difference of two squares method. When a quadratic contains two terms where each of ...
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How to solve a quadratic equation
We find two factors of the product of the constant term (the term with no variable) and the coefficient of the squared variable whose sum gives the linear term. These factors are now placed in ...
Sometimes we have to factorise quadratics such as 4\({x^2}\) - 19\({x}\) + 12. These are made much more difficult by the fact that there is a number (4) in front of the \({x^2}\) term (we say that the ...
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